问题:子类继承父类,构造函数及公共属性的执行顺序是怎样的?

  示例代码

<SPAN style="FONT-FAMILY: Times New Roman; FONT-SIZE: 14px">public class A extends C {
 B b = new B();
 static H h = new H();
 static {
  System.out.println("this is static tack");
 }

 static void i() {
  System.out.println("this is static metod");
 }

 public A() {
  System.out.println("this is class A");

 }

 public static void main(String[] args) {
  A a = new A();
 }
}

class B {
 public B() {
  System.out.println("this is class B");
 }
}

class C {
 D d = new D();
 static E e = new E();
 final F e1 = new F();
 static final G e2 = new G();

 public C() {
  System.out.println("this is class C");
 }
}

class D {
 public D() {
  System.out.println("this is class D");
 }
}

class E {
 public E() {
  System.out.println("this is class E");
 }
}

class F {
 public F() {
  System.out.println("this is class F");
 }
}

class G {
 public G() {
  System.out.println("this is class G");
 }
}

class H {
 public H() {
  System.out.println("this is class H");
 }
}</SPAN>

 

执行结果:

  this is class E
  this is class G
  this is class H
  this is static tack
  this is class D
  this is class F
  this is class C
  this is class B
  this is class A

  执行顺序:

  1、实现父类公共的静态属性或静态的块级代码

  2、实现本身的公共的静态属性

  3、实现父类公共属性

  4、执行父类的构造方法

  5、实现本身的公共属性

  6、执行本身的构造函数

  7、静态方法不执行

  补充:

  当父类有多个构造函数,若子类用super(参数信息)指明调用父类有参数的构造函数,则不执行无参数的构造方法